Diagonalization Theorem

is diagonalizable iff eigenvectors of are a basis for .

Given that A is diagonalizable, the jth column of P will contain the jth vector from the basis of eigenvectors, and the jth column of the diagonal matrix D will contain the corresponding eigenvalue in the (j, j)−entry

See examples in lecture notes.

Corollary 1

is diagonalizable iff for every of .

Corollary 2

If has eigenvalues, then is diagonalizable.