Diagonalization Theorem
is diagonalizable iff eigenvectors of are a basis for .
Given that A is diagonalizable, the jth column of P will contain the jth vector from the basis of eigenvectors, and the jth column of the diagonal matrix D will contain the corresponding eigenvalue in the (j, j)−entry
See examples in lecture notes.
Corollary 1
is diagonalizable iff for every of .
Corollary 2
If has eigenvalues, then is diagonalizable.